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11041131341 is a prime number
BaseRepresentation
bin10100100100001101…
…00100101101001101
31001111110211120211102
422102012210231031
5140103012200331
65023333432445
7540416032202
oct122206445515
931443746742
1011041131341
114756481439
12218179b725
13106c5c9116
1476a539ca9
154494b64cb
hex2921a4b4d

11041131341 has 2 divisors, whose sum is σ = 11041131342. Its totient is φ = 11041131340.

The previous prime is 11041131323. The next prime is 11041131359. The reversal of 11041131341 is 14313114011.

It is a balanced prime because it is at equal distance from previous prime (11041131323) and next prime (11041131359).

It can be written as a sum of positive squares in only one way, i.e., 10846389316 + 194742025 = 104146^2 + 13955^2 .

It is a cyclic number.

It is not a de Polignac number, because 11041131341 - 218 = 11040869197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11041331341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520565670 + 5520565671.

It is an arithmetic number, because the mean of its divisors is an integer number (5520565671).

Almost surely, 211041131341 is an apocalyptic number.

It is an amenable number.

11041131341 is a deficient number, since it is larger than the sum of its proper divisors (1).

11041131341 is an equidigital number, since it uses as much as digits as its factorization.

11041131341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11041131341 its reverse (14313114011), we get a palindrome (25354245352).

The spelling of 11041131341 in words is "eleven billion, forty-one million, one hundred thirty-one thousand, three hundred forty-one".