Base | Representation |
---|---|
bin | 10000000100010011010… |
… | …011010111110010001011 |
3 | 10220112221202012212200021 |
4 | 100010103103113302023 |
5 | 121042224343042311 |
6 | 2203121443121311 |
7 | 142525244614432 |
oct | 20042323276213 |
9 | 3815852185607 |
10 | 1104130440331 |
11 | 396293937a46 |
12 | 159ba3073237 |
13 | 8017173a9c9 |
14 | 3b623c94119 |
15 | 1dac33e0171 |
hex | 101134d7c8b |
1104130440331 has 2 divisors, whose sum is σ = 1104130440332. Its totient is φ = 1104130440330.
The previous prime is 1104130440323. The next prime is 1104130440359. The reversal of 1104130440331 is 1330440314011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104130440331 - 23 = 1104130440323 is a prime.
It is a super-2 number, since 2×11041304403312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1104130440296 and 1104130440305.
It is not a weakly prime, because it can be changed into another prime (1104130440031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552065220165 + 552065220166.
It is an arithmetic number, because the mean of its divisors is an integer number (552065220166).
Almost surely, 21104130440331 is an apocalyptic number.
1104130440331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104130440331 is an equidigital number, since it uses as much as digits as its factorization.
1104130440331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1104130440331 its reverse (1330440314011), we get a palindrome (2434570754342).
The spelling of 1104130440331 in words is "one trillion, one hundred four billion, one hundred thirty million, four hundred forty thousand, three hundred thirty-one".
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