11041313420023 has 4 divisors (see below), whose sum is σ = 11041321211080. Its totient is φ = 11041305628968.

The previous prime is 11041313420017. The next prime is 11041313420099. The reversal of 11041313420023 is 32002431314011.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11041313420023 - 2¹³ = 11041313411831 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11041313420023.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11041313420003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1102008 + ... + 4826701.

It is an arithmetic number, because the mean of its divisors is an integer number (2760330302770).

Almost surely, 2^{11041313420023} is an apocalyptic number.

11041313420023 is a deficient number, since it is larger than the sum of its proper divisors (7791057).

11041313420023 is an equidigital number, since it uses as much as digits as its factorization.

11041313420023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7791056.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11041313420023 its reverse (32002431314011), we get a palindrome (43043744734034).

The spelling of 11041313420023 in words is "eleven trillion, forty-one billion, three hundred thirteen million, four hundred twenty thousand, twenty-three".