Search a number
-
+
110413134553 is a prime number
BaseRepresentation
bin110011011010100100…
…0101011101011011001
3101112222212210101102211
41212311020223223121
53302111230301203
6122420104355121
710656066105241
oct1466510535331
9345885711384
10110413134553
114290a377227
1219495175aa1
13a547c89a17
1454b6006b21
152d13502c6d
hex19b522bad9

110413134553 has 2 divisors, whose sum is σ = 110413134554. Its totient is φ = 110413134552.

The previous prime is 110413134551. The next prime is 110413134617. The reversal of 110413134553 is 355431314011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108028570329 + 2384564224 = 328677^2 + 48832^2 .

It is an emirp because it is prime and its reverse (355431314011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110413134553 - 21 = 110413134551 is a prime.

Together with 110413134551, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (110413134551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55206567276 + 55206567277.

It is an arithmetic number, because the mean of its divisors is an integer number (55206567277).

Almost surely, 2110413134553 is an apocalyptic number.

It is an amenable number.

110413134553 is a deficient number, since it is larger than the sum of its proper divisors (1).

110413134553 is an equidigital number, since it uses as much as digits as its factorization.

110413134553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 110413134553 its reverse (355431314011), we get a palindrome (465844448564).

The spelling of 110413134553 in words is "one hundred ten billion, four hundred thirteen million, one hundred thirty-four thousand, five hundred fifty-three".