Base | Representation |
---|---|
bin | 110011011010100100… |
… | …0101011101011011001 |
3 | 101112222212210101102211 |
4 | 1212311020223223121 |
5 | 3302111230301203 |
6 | 122420104355121 |
7 | 10656066105241 |
oct | 1466510535331 |
9 | 345885711384 |
10 | 110413134553 |
11 | 4290a377227 |
12 | 19495175aa1 |
13 | a547c89a17 |
14 | 54b6006b21 |
15 | 2d13502c6d |
hex | 19b522bad9 |
110413134553 has 2 divisors, whose sum is σ = 110413134554. Its totient is φ = 110413134552.
The previous prime is 110413134551. The next prime is 110413134617. The reversal of 110413134553 is 355431314011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108028570329 + 2384564224 = 328677^2 + 48832^2 .
It is an emirp because it is prime and its reverse (355431314011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110413134553 - 21 = 110413134551 is a prime.
Together with 110413134551, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (110413134551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55206567276 + 55206567277.
It is an arithmetic number, because the mean of its divisors is an integer number (55206567277).
Almost surely, 2110413134553 is an apocalyptic number.
It is an amenable number.
110413134553 is a deficient number, since it is larger than the sum of its proper divisors (1).
110413134553 is an equidigital number, since it uses as much as digits as its factorization.
110413134553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 110413134553 its reverse (355431314011), we get a palindrome (465844448564).
The spelling of 110413134553 in words is "one hundred ten billion, four hundred thirteen million, one hundred thirty-four thousand, five hundred fifty-three".
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