Base | Representation |
---|---|
bin | 10000000100010011011… |
… | …010011101111100001001 |
3 | 10220112221212201101102101 |
4 | 100010103122131330021 |
5 | 121042230332104203 |
6 | 2203121551033401 |
7 | 142525266463012 |
oct | 20042332357411 |
9 | 3815855641371 |
10 | 1104132300553 |
11 | 396294998617 |
12 | 159ba380b861 |
13 | 80171c3c629 |
14 | 3b62421a009 |
15 | 1dac365b41d |
hex | 1011369df09 |
1104132300553 has 4 divisors (see below), whose sum is σ = 1104153333520. Its totient is φ = 1104111267588.
The previous prime is 1104132300533. The next prime is 1104132300559. The reversal of 1104132300553 is 3550032314011.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1104132300553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1104132300559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10437543 + ... + 10542796.
It is an arithmetic number, because the mean of its divisors is an integer number (276038333380).
Almost surely, 21104132300553 is an apocalyptic number.
It is an amenable number.
1104132300553 is a deficient number, since it is larger than the sum of its proper divisors (21032967).
1104132300553 is an equidigital number, since it uses as much as digits as its factorization.
1104132300553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21032966.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 1104132300553 its reverse (3550032314011), we get a palindrome (4654164614564).
The spelling of 1104132300553 in words is "one trillion, one hundred four billion, one hundred thirty-two million, three hundred thousand, five hundred fifty-three".
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