Base | Representation |
---|---|
bin | 1010000010101100100000… |
… | …0110100111111001110110 |
3 | 1110002112211202120201110221 |
4 | 2200223020012213321312 |
5 | 2421400313310131410 |
6 | 35252205413004554 |
7 | 2216500521034003 |
oct | 240531006477166 |
9 | 43075752521427 |
10 | 11041423130230 |
11 | 3577706564839 |
12 | 12a3a9a32375a |
13 | 6212812931bc |
14 | 2a259cb568aa |
15 | 14232d0a44da |
hex | a0ac81a7e76 |
11041423130230 has 32 divisors (see below), whose sum is σ = 21048938438400. Its totient is φ = 4158448790112.
The previous prime is 11041423130219. The next prime is 11041423130263. The reversal of 11041423130230 is 3203132414011.
It is a junction number, because it is equal to n+sod(n) for n = 11041423130195 and 11041423130204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 178229010 + ... + 178290949.
It is an arithmetic number, because the mean of its divisors is an integer number (657779326200).
Almost surely, 211041423130230 is an apocalyptic number.
11041423130230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11041423130230 is a deficient number, since it is larger than the sum of its proper divisors (10007515308170).
11041423130230 is a wasteful number, since it uses less digits than its factorization.
11041423130230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 356520148.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11041423130230 its reverse (3203132414011), we get a palindrome (14244555544241).
The spelling of 11041423130230 in words is "eleven trillion, forty-one billion, four hundred twenty-three million, one hundred thirty thousand, two hundred thirty".
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