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11042000131 = 47234936173
BaseRepresentation
bin10100100100010011…
…11000110100000011
31001111112110201120211
422102021320310003
5140103223001011
65023404214551
7540426311131
oct122211706403
931445421524
1011042000131
114756a15148
122181b3a457
13106c8416b6
1476a6c4751
154495d8b21
hex292278d03

11042000131 has 4 divisors (see below), whose sum is σ = 11276936352. Its totient is φ = 10807063912.

The previous prime is 11042000111. The next prime is 11042000161. The reversal of 11042000131 is 13100024011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13100024011 = 37354054703.

It is a cyclic number.

It is not a de Polignac number, because 11042000131 - 27 = 11042000003 is a prime.

It is a super-2 number, since 2×110420001312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11042000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117468040 + ... + 117468133.

It is an arithmetic number, because the mean of its divisors is an integer number (2819234088).

Almost surely, 211042000131 is an apocalyptic number.

11042000131 is a deficient number, since it is larger than the sum of its proper divisors (234936221).

11042000131 is an equidigital number, since it uses as much as digits as its factorization.

11042000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 234936220.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11042000131 its reverse (13100024011), we get a palindrome (24142024142).

The spelling of 11042000131 in words is "eleven billion, forty-two million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 47 234936173 11042000131