Base | Representation |
---|---|
bin | 11001000110110101000001… |
… | …010100010000001011000111 |
3 | 112110222002101020012122220111 |
4 | 121012311001110100023013 |
5 | 103433111444432303111 |
6 | 1030502234110013451 |
7 | 32154416461066426 |
oct | 3106650124201307 |
9 | 473862336178814 |
10 | 110420410041031 |
11 | 3220203a8a54a2 |
12 | 1047426baa7287 |
13 | 497c7a523314c |
14 | 1d3a53aa452bd |
15 | cb744cd70a21 |
hex | 646d415102c7 |
110420410041031 has 4 divisors (see below), whose sum is σ = 113982358752064. Its totient is φ = 106858461330000.
The previous prime is 110420410040971. The next prime is 110420410041041. The reversal of 110420410041031 is 130140014024011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110420410041031 - 29 = 110420410040519 is a prime.
It is a super-3 number, since 3×1104204100410313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110420410040993 and 110420410041011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110420410041041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1780974355470 + ... + 1780974355531.
It is an arithmetic number, because the mean of its divisors is an integer number (28495589688016).
Almost surely, 2110420410041031 is an apocalyptic number.
110420410041031 is a deficient number, since it is larger than the sum of its proper divisors (3561948711033).
110420410041031 is an equidigital number, since it uses as much as digits as its factorization.
110420410041031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3561948711032.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 110420410041031 its reverse (130140014024011), we get a palindrome (240560424065042).
The spelling of 110420410041031 in words is "one hundred ten trillion, four hundred twenty billion, four hundred ten million, forty-one thousand, thirty-one".
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