11042121113 has 4 divisors (see below), whose sum is σ = 11422883940. Its totient is φ = 10661358288.

The previous prime is 11042121053. The next prime is 11042121137. The reversal of 11042121113 is 31112124011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31112124011 = 161947 ⋅192113.

It can be written as a sum of positive squares in 2 ways, for example, as 1919578969 + 9122542144 = 43813^2 + 95512^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11042121113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11042121091 and 11042121100.

It is not an unprimeable number, because it can be changed into a prime (11042121173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190381370 + ... + 190381427.

It is an arithmetic number, because the mean of its divisors is an integer number (2855720985).

Almost surely, 2^11042121113 is an apocalyptic number.

It is an amenable number.

11042121113 is a deficient number, since it is larger than the sum of its proper divisors (380762827).

11042121113 is an equidigital number, since it uses as much as digits as its factorization.

11042121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380762826.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11042121113 its reverse (31112124011), we get a palindrome (42154245124).

The spelling of 11042121113 in words is "eleven billion, forty-two million, one hundred twenty-one thousand, one hundred thirteen".