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11043031142041 is a prime number
BaseRepresentation
bin1010000010110010011111…
…1100101100111010011001
31110002200222211100011222221
42200230213330230322121
52421412111433021131
635253033134144041
72216555414643043
oct240544774547231
943080884304887
1011043031142041
113578361208918
1212a4268952021
13621479472892
142a26b2534a93
151423c4337411
hexa0b27f2ce99

11043031142041 has 2 divisors, whose sum is σ = 11043031142042. Its totient is φ = 11043031142040.

The previous prime is 11043031141997. The next prime is 11043031142123. The reversal of 11043031142041 is 14024113034011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9036162252441 + 2006868889600 = 3006021^2 + 1416640^2 .

It is a cyclic number.

It is not a de Polignac number, because 11043031142041 - 29 = 11043031141529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11043031141997 and 11043031142015.

It is not a weakly prime, because it can be changed into another prime (11043031142141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521515571020 + 5521515571021.

It is an arithmetic number, because the mean of its divisors is an integer number (5521515571021).

Almost surely, 211043031142041 is an apocalyptic number.

It is an amenable number.

11043031142041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043031142041 is an equidigital number, since it uses as much as digits as its factorization.

11043031142041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 11043031142041 its reverse (14024113034011), we get a palindrome (25067144176052).

The spelling of 11043031142041 in words is "eleven trillion, forty-three billion, thirty-one million, one hundred forty-two thousand, forty-one".