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11043315344213 is a prime number
BaseRepresentation
bin1010000010110011100011…
…1000110110001101010101
31110002201201122010011002022
42200230320320312031111
52421413202212003323
635253121245422525
72216565435424565
oct240547070661525
943081648104068
1011043315344213
113578497682149
1212a4327b6aa45
136214c32cbb49
142a26dc194da5
151423de2754c8
hexa0b38e36355

11043315344213 has 2 divisors, whose sum is σ = 11043315344214. Its totient is φ = 11043315344212.

The previous prime is 11043315344209. The next prime is 11043315344219. The reversal of 11043315344213 is 31244351334011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7066968274129 + 3976347070084 = 2658377^2 + 1994078^2 .

It is a cyclic number.

It is not a de Polignac number, because 11043315344213 - 22 = 11043315344209 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11043315344219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521657672106 + 5521657672107.

It is an arithmetic number, because the mean of its divisors is an integer number (5521657672107).

Almost surely, 211043315344213 is an apocalyptic number.

It is an amenable number.

11043315344213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043315344213 is an equidigital number, since it uses as much as digits as its factorization.

11043315344213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 11043315344213 its reverse (31244351334011), we get a palindrome (42287666678224).

The spelling of 11043315344213 in words is "eleven trillion, forty-three billion, three hundred fifteen million, three hundred forty-four thousand, two hundred thirteen".