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1104332022217 is a prime number
BaseRepresentation
bin10000000100011111010…
…100010110000111001001
310220120110210112022001001
4100010133110112013021
5121043132444202332
62203153443455001
7142533243210634
oct20043724260711
93816423468031
101104332022217
11396387700446
1215a03a687461
13801a442a028
143b642968c1b
151dad5e5d0e7
hex1011f5161c9

1104332022217 has 2 divisors, whose sum is σ = 1104332022218. Its totient is φ = 1104332022216.

The previous prime is 1104332022187. The next prime is 1104332022289. The reversal of 1104332022217 is 7122202334011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 747306651961 + 357025370256 = 864469^2 + 597516^2 .

It is an emirp because it is prime and its reverse (7122202334011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1104332022217 - 231 = 1102184538569 is a prime.

It is not a weakly prime, because it can be changed into another prime (1104332022317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552166011108 + 552166011109.

It is an arithmetic number, because the mean of its divisors is an integer number (552166011109).

Almost surely, 21104332022217 is an apocalyptic number.

It is an amenable number.

1104332022217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104332022217 is an equidigital number, since it uses as much as digits as its factorization.

1104332022217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 1104332022217 its reverse (7122202334011), we get a palindrome (8226534356228).

The spelling of 1104332022217 in words is "one trillion, one hundred four billion, three hundred thirty-two million, twenty-two thousand, two hundred seventeen".