Base | Representation |
---|---|
bin | 10100100100011101… |
… | …11100010011100001 |
3 | 1001111121222001011201 |
4 | 22102032330103201 |
5 | 140104042401103 |
6 | 5023452441201 |
7 | 540443500150 |
oct | 122216742341 |
9 | 31447861151 |
10 | 11043325153 |
11 | 475773a703 |
12 | 2182479201 |
13 | 106cbb6833 |
14 | 76a94b597 |
15 | 44979b51d |
hex | 2923bc4e1 |
11043325153 has 16 divisors (see below), whose sum is σ = 12764459520. Its totient is φ = 9358344000.
The previous prime is 11043325127. The next prime is 11043325159. The reversal of 11043325153 is 35152334011.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11043325153 - 29 = 11043324641 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11043325159) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 490248 + ... + 512278.
It is an arithmetic number, because the mean of its divisors is an integer number (797778720).
Almost surely, 211043325153 is an apocalyptic number.
It is an amenable number.
11043325153 is a deficient number, since it is larger than the sum of its proper divisors (1721134367).
11043325153 is a wasteful number, since it uses less digits than its factorization.
11043325153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22848.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 11043325153 its reverse (35152334011), we get a palindrome (46195659164).
The spelling of 11043325153 in words is "eleven billion, forty-three million, three hundred twenty-five thousand, one hundred fifty-three".
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