Base | Representation |
---|---|
bin | 1010000010110011100111… |
… | …0010011010000001111001 |
3 | 1110002201202200111202012122 |
4 | 2200230321302122001321 |
5 | 2421413220042330040 |
6 | 35253122545051025 |
7 | 2216566010610623 |
oct | 240547162320171 |
9 | 43081680452178 |
10 | 11043330433145 |
11 | 35784a514873a |
12 | 12a4331026a75 |
13 | 6214c6482aca |
14 | 2a27001a1c13 |
15 | 1423e07561b5 |
hex | a0b39c9a079 |
11043330433145 has 16 divisors (see below), whose sum is σ = 13643435352720. Its totient is φ = 8574872730624.
The previous prime is 11043330433139. The next prime is 11043330433151. The reversal of 11043330433145 is 54133403334011.
It is an interprime number because it is at equal distance from previous prime (11043330433139) and next prime (11043330433151).
It can be written as a sum of positive squares in 8 ways, for example, as 2971117558249 + 8072212874896 = 1723693^2 + 2841164^2 .
It is a cyclic number.
It is not a de Polignac number, because 11043330433145 - 214 = 11043330416761 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72899492 + ... + 73050821.
It is an arithmetic number, because the mean of its divisors is an integer number (852714709545).
Almost surely, 211043330433145 is an apocalyptic number.
It is an amenable number.
11043330433145 is a deficient number, since it is larger than the sum of its proper divisors (2600104919575).
11043330433145 is a wasteful number, since it uses less digits than its factorization.
11043330433145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145950764.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 11043330433145 its reverse (54133403334011), we get a palindrome (65176733767156).
The spelling of 11043330433145 in words is "eleven trillion, forty-three billion, three hundred thirty million, four hundred thirty-three thousand, one hundred forty-five".
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