Base | Representation |
---|---|
bin | 1010000010110011101001… |
… | …1001110101111010111111 |
3 | 1110002201210101221222002102 |
4 | 2200230322121311322333 |
5 | 2421413230214133012 |
6 | 35253123554415315 |
7 | 2216566164515306 |
oct | 240547231657277 |
9 | 43081711858072 |
10 | 11043340771007 |
11 | 35784aaa69726 |
12 | 12a433459153b |
13 | 6214c866239c |
14 | 2a27016d343d |
15 | 1423e15e92c2 |
hex | a0b3a675ebf |
11043340771007 has 2 divisors, whose sum is σ = 11043340771008. Its totient is φ = 11043340771006.
The previous prime is 11043340771003. The next prime is 11043340771013. The reversal of 11043340771007 is 70017704334011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11043340771007 - 22 = 11043340771003 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11043340771003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521670385503 + 5521670385504.
It is an arithmetic number, because the mean of its divisors is an integer number (5521670385504).
Almost surely, 211043340771007 is an apocalyptic number.
11043340771007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043340771007 is an equidigital number, since it uses as much as digits as its factorization.
11043340771007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 49392, while the sum is 38.
The spelling of 11043340771007 in words is "eleven trillion, forty-three billion, three hundred forty million, seven hundred seventy-one thousand, seven".
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