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11043341211004 = 224388372712879
BaseRepresentation
bin1010000010110011101001…
…1011100001010101111100
31110002201210102210022122121
42200230322123201111330
52421413230322223004
635253124012052324
72216566201330144
oct240547233412574
943081712708577
1011043341211004
11357850023a263
1212a43347640a4
136214c878773b
142a27017a9924
151423e1684854
hexa0b3a6e157c

11043341211004 has 24 divisors (see below), whose sum is σ = 19797681263360. Its totient is φ = 5387151705264.

The previous prime is 11043341210971. The next prime is 11043341211031. The reversal of 11043341211004 is 40011214334011.

11043341211004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a self number, because there is not a number n which added to its sum of digits gives 11043341211004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36204564 + ... + 36508315.

Almost surely, 211043341211004 is an apocalyptic number.

It is an amenable number.

11043341211004 is a deficient number, since it is larger than the sum of its proper divisors (8754340052356).

11043341211004 is a wasteful number, since it uses less digits than its factorization.

11043341211004 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72713809 (or 72713807 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 11043341211004 its reverse (40011214334011), we get a palindrome (51054555545015).

The spelling of 11043341211004 in words is "eleven trillion, forty-three billion, three hundred forty-one million, two hundred eleven thousand, four".

Divisors: 1 2 4 43 86 172 883 1766 3532 37969 75938 151876 72712879 145425758 290851516 3126653797 6253307594 12506615188 64205472157 128410944314 256821888628 2760835302751 5521670605502 11043341211004