Base | Representation |
---|---|
bin | 1010000010110110000111… |
… | …1100101011001110010010 |
3 | 1110002210111122100100022011 |
4 | 2200231201330223032102 |
5 | 2421421110034314100 |
6 | 35253313454333134 |
7 | 2216621501630362 |
oct | 240554174531622 |
9 | 43083448310264 |
10 | 11044004213650 |
11 | 3578810509a31 |
12 | 12a449a7ba1aa |
13 | 6215a2c41bb5 |
14 | 2a27658729a2 |
15 | 14242e999bba |
hex | a0b61f2b392 |
11044004213650 has 24 divisors (see below), whose sum is σ = 20542666528944. Its totient is φ = 4417425622800.
The previous prime is 11044004213633. The next prime is 11044004213651. The reversal of 11044004213650 is 5631240044011.
It is a super-2 number, since 2×110440042136502 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11044004213651) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3130836 + ... + 5647135.
It is an arithmetic number, because the mean of its divisors is an integer number (855944438706).
Almost surely, 211044004213650 is an apocalyptic number.
11044004213650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11044004213650 is a deficient number, since it is larger than the sum of its proper divisors (9498662315294).
11044004213650 is a wasteful number, since it uses less digits than its factorization.
11044004213650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8803146 (or 8803141 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11044004213650 its reverse (5631240044011), we get a palindrome (16675244257661).
The spelling of 11044004213650 in words is "eleven trillion, forty-four billion, four million, two hundred thirteen thousand, six hundred fifty".
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