Base | Representation |
---|---|
bin | 10100100100100100… |
… | …10001111001000001 |
3 | 1001111200121111020111 |
4 | 22102102101321001 |
5 | 140104303400001 |
6 | 5023523311321 |
7 | 540454102552 |
oct | 122222217101 |
9 | 31450544214 |
10 | 11044200001 |
11 | 4758187a1a |
12 | 218281b541 |
13 | 1070131ab3 |
14 | 76aad8329 |
15 | 4498c0851 |
hex | 292491e41 |
11044200001 has 2 divisors, whose sum is σ = 11044200002. Its totient is φ = 11044200000.
The previous prime is 11044199993. The next prime is 11044200019. The reversal of 11044200001 is 10000244011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9813874225 + 1230325776 = 99065^2 + 35076^2 .
It is an emirp because it is prime and its reverse (10000244011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11044200001 - 23 = 11044199993 is a prime.
It is not a weakly prime, because it can be changed into another prime (11044200031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522100000 + 5522100001.
It is an arithmetic number, because the mean of its divisors is an integer number (5522100001).
Almost surely, 211044200001 is an apocalyptic number.
It is an amenable number.
11044200001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11044200001 is an equidigital number, since it uses as much as digits as its factorization.
11044200001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 13.
Adding to 11044200001 its reverse (10000244011), we get a palindrome (21044444012).
The spelling of 11044200001 in words is "eleven billion, forty-four million, two hundred thousand, one".
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