Base | Representation |
---|---|
bin | 10100100100100100… |
… | …10001111001000011 |
3 | 1001111200121111020120 |
4 | 22102102101321003 |
5 | 140104303400003 |
6 | 5023523311323 |
7 | 540454102554 |
oct | 122222217103 |
9 | 31450544216 |
10 | 11044200003 |
11 | 4758187a21 |
12 | 218281b543 |
13 | 1070131ab5 |
14 | 76aad832b |
15 | 4498c0853 |
hex | 292491e43 |
11044200003 has 8 divisors (see below), whose sum is σ = 14927320848. Its totient is φ = 7261939584.
The previous prime is 11044200001. The next prime is 11044200019. The reversal of 11044200003 is 30000244011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11044200003 - 21 = 11044200001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11044200001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25214850 + ... + 25215287.
It is an arithmetic number, because the mean of its divisors is an integer number (1865915106).
Almost surely, 211044200003 is an apocalyptic number.
11044200003 is a deficient number, since it is larger than the sum of its proper divisors (3883120845).
11044200003 is an equidigital number, since it uses as much as digits as its factorization.
11044200003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50430213.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 11044200003 its reverse (30000244011), we get a palindrome (41044444014).
The spelling of 11044200003 in words is "eleven billion, forty-four million, two hundred thousand, three".
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