Base | Representation |
---|---|
bin | 1010000010110111000000… |
… | …1100111000011100011111 |
3 | 1110002211010022022101021202 |
4 | 2200231300030320130133 |
5 | 2421422102243440020 |
6 | 35253353315550115 |
7 | 2216630434326032 |
oct | 240556014703437 |
9 | 43084108271252 |
10 | 11044243343135 |
11 | 3578923498502 |
12 | 12a45468bb33b |
13 | 621610649732 |
14 | 2a278951d019 |
15 | 142445982e75 |
hex | a0b7033871f |
11044243343135 has 32 divisors (see below), whose sum is σ = 13593796634880. Its totient is φ = 8609263423488.
The previous prime is 11044243343101. The next prime is 11044243343149. The reversal of 11044243343135 is 53134334244011.
It is a cyclic number.
It is not a de Polignac number, because 11044243343135 - 28 = 11044243342879 is a prime.
It is a super-2 number, since 2×110442433431352 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 187132511 + ... + 187191519.
It is an arithmetic number, because the mean of its divisors is an integer number (424806144840).
Almost surely, 211044243343135 is an apocalyptic number.
11044243343135 is a deficient number, since it is larger than the sum of its proper divisors (2549553291745).
11044243343135 is a wasteful number, since it uses less digits than its factorization.
11044243343135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61127.
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 11044243343135 its reverse (53134334244011), we get a palindrome (64178577587146).
The spelling of 11044243343135 in words is "eleven trillion, forty-four billion, two hundred forty-three million, three hundred forty-three thousand, one hundred thirty-five".
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