Base | Representation |
---|---|
bin | 10000000100100101010… |
… | …011010101010010110101 |
3 | 10220120201210110000221020 |
4 | 100010211103111102311 |
5 | 121043334144420041 |
6 | 2203211431411353 |
7 | 142535602450620 |
oct | 20044523252265 |
9 | 3816653400836 |
10 | 1104432420021 |
11 | 396429343837 |
12 | 15a068223b59 |
13 | 801bc17c908 |
14 | 3b652020db7 |
15 | 1dadeb90866 |
hex | 101254d54b5 |
1104432420021 has 16 divisors (see below), whose sum is σ = 1684894777344. Its totient is φ = 630372938544.
The previous prime is 1104432420019. The next prime is 1104432420041. The reversal of 1104432420021 is 1200242344011.
It is not a de Polignac number, because 1104432420021 - 21 = 1104432420019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1104432419973 and 1104432420000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1104432420001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30452341 + ... + 30488586.
It is an arithmetic number, because the mean of its divisors is an integer number (105305923584).
Almost surely, 21104432420021 is an apocalyptic number.
It is an amenable number.
1104432420021 is a deficient number, since it is larger than the sum of its proper divisors (580462357323).
1104432420021 is an equidigital number, since it uses as much as digits as its factorization.
1104432420021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60941800.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1104432420021 its reverse (1200242344011), we get a palindrome (2304674764032).
The spelling of 1104432420021 in words is "one trillion, one hundred four billion, four hundred thirty-two million, four hundred twenty thousand, twenty-one".
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