Base | Representation |
---|---|
bin | 1010000010110111011010… |
… | …0011111000001010101001 |
3 | 1110002211101202001212110112 |
4 | 2200231312203320022221 |
5 | 2421422312102101401 |
6 | 35253412050424105 |
7 | 2216633201230622 |
oct | 240556643701251 |
9 | 43084352055415 |
10 | 11044350034601 |
11 | 357897873a374 |
12 | 12a4576592035 |
13 | 621629793b90 |
14 | 2a2799772a49 |
15 | 14245000a3bb |
hex | a0b768f82a9 |
11044350034601 has 16 divisors (see below), whose sum is σ = 12118636164096. Its totient is φ = 10002176623296.
The previous prime is 11044350034589. The next prime is 11044350034657. The reversal of 11044350034601 is 10643005344011.
It is a happy number.
It is not a de Polignac number, because 11044350034601 - 214 = 11044350018217 is a prime.
It is a super-2 number, since 2×110443500346012 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11044350094601) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30316136 + ... + 30678278.
It is an arithmetic number, because the mean of its divisors is an integer number (757414760256).
Almost surely, 211044350034601 is an apocalyptic number.
It is an amenable number.
11044350034601 is a deficient number, since it is larger than the sum of its proper divisors (1074286129495).
11044350034601 is a wasteful number, since it uses less digits than its factorization.
11044350034601 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 406472.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 11044350034601 its reverse (10643005344011), we get a palindrome (21687355378612).
The spelling of 11044350034601 in words is "eleven trillion, forty-four billion, three hundred fifty million, thirty-four thousand, six hundred one".
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