110445304873 has 4 divisors (see below), whose sum is σ = 110445976260. Its totient is φ = 110444633488.

The previous prime is 110445304861. The next prime is 110445304913. The reversal of 110445304873 is 378403544011.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 378403544011 = 2539 ⋅149036449.

It can be written as a sum of positive squares in 2 ways, for example, as 42943029529 + 67502275344 = 207227^2 + 259812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110445304873 is a prime.

It is a super-2 number, since 2×110445304873² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110445304373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96783 + ... + 479851.

It is an arithmetic number, because the mean of its divisors is an integer number (27611494065).

Almost surely, 2^110445304873 is an apocalyptic number.

It is an amenable number.

110445304873 is a deficient number, since it is larger than the sum of its proper divisors (671387).

110445304873 is an equidigital number, since it uses as much as digits as its factorization.

110445304873 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671386.

The product of its (nonzero) digits is 161280, while the sum is 40.

Adding to 110445304873 its reverse (378403544011), we get a palindrome (488848848884).

The spelling of 110445304873 in words is "one hundred ten billion, four hundred forty-five million, three hundred four thousand, eight hundred seventy-three".