Base | Representation |
---|---|
bin | 1011000000110101001… |
… | …10111101101111001011 |
3 | 1100011201121000201211111 |
4 | 11200122212331233023 |
5 | 22144432301402021 |
6 | 445500341111151 |
7 | 36224123024323 |
oct | 5403246755713 |
9 | 1304647021744 |
10 | 378403544011 |
11 | 136530a32369 |
12 | 614066b84b7 |
13 | 298b629babc |
14 | 14459c6a283 |
15 | 9c9a92d8e1 |
hex | 581a9bdbcb |
378403544011 has 4 divisors (see below), whose sum is σ = 378552583000. Its totient is φ = 378254505024.
The previous prime is 378403543993. The next prime is 378403544027. The reversal of 378403544011 is 110445304873.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110445304873 = 288317 ⋅383069.
It is a cyclic number.
It is not a de Polignac number, because 378403544011 - 25 = 378403543979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (378403541011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74515686 + ... + 74520763.
It is an arithmetic number, because the mean of its divisors is an integer number (94638145750).
Almost surely, 2378403544011 is an apocalyptic number.
378403544011 is a deficient number, since it is larger than the sum of its proper divisors (149038989).
378403544011 is a wasteful number, since it uses less digits than its factorization.
378403544011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149038988.
The product of its (nonzero) digits is 161280, while the sum is 40.
Adding to 378403544011 its reverse (110445304873), we get a palindrome (488848848884).
The spelling of 378403544011 in words is "three hundred seventy-eight billion, four hundred three million, five hundred forty-four thousand, eleven".
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