11045313003 has 4 divisors (see below), whose sum is σ = 14727084008. Its totient is φ = 7363542000.

The previous prime is 11045312987. The next prime is 11045313007. The reversal of 11045313003 is 30031354011.

11045313003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30031354011 = 3 ⋅10010451337.

It is not a de Polignac number, because 11045313003 - 2⁴ = 11045312987 is a prime.

It is a super-3 number, since 3×11045313003³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11045313007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1840885498 + ... + 1840885503.

It is an arithmetic number, because the mean of its divisors is an integer number (3681771002).

Almost surely, 2^11045313003 is an apocalyptic number.

11045313003 is a deficient number, since it is larger than the sum of its proper divisors (3681771005).

11045313003 is an equidigital number, since it uses as much as digits as its factorization.

11045313003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3681771004.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 11045313003 its reverse (30031354011), we get a palindrome (41076667014).

The spelling of 11045313003 in words is "eleven billion, forty-five million, three hundred thirteen thousand, three".