Base | Representation |
---|---|
bin | 1010000010111110101011… |
… | …1111000010100010101111 |
3 | 1110010000102212111122101122 |
4 | 2200233222333002202233 |
5 | 2421440312121441142 |
6 | 35254333544131155 |
7 | 2220032456635223 |
oct | 240575277024257 |
9 | 43100385448348 |
10 | 11046303312047 |
11 | 3579790274653 |
12 | 12a4a20766abb |
13 | 62187b35c853 |
14 | 2a2902d48783 |
15 | 14251673e1d2 |
hex | a0beafc28af |
11046303312047 has 2 divisors, whose sum is σ = 11046303312048. Its totient is φ = 11046303312046.
The previous prime is 11046303312007. The next prime is 11046303312061. The reversal of 11046303312047 is 74021330364011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11046303312047 - 242 = 6648256800943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11046303311998 and 11046303312016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11046303312007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5523151656023 + 5523151656024.
It is an arithmetic number, because the mean of its divisors is an integer number (5523151656024).
Almost surely, 211046303312047 is an apocalyptic number.
11046303312047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11046303312047 is an equidigital number, since it uses as much as digits as its factorization.
11046303312047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 11046303312047 its reverse (74021330364011), we get a palindrome (85067633676058).
The spelling of 11046303312047 in words is "eleven trillion, forty-six billion, three hundred three million, three hundred twelve thousand, forty-seven".
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