Base | Representation |
---|---|
bin | 10100100101000100… |
… | …00000111000011101 |
3 | 1001111222101001011210 |
4 | 22102202000320131 |
5 | 140111332342022 |
6 | 5024151535033 |
7 | 540534132000 |
oct | 122242007035 |
9 | 31458331153 |
10 | 11048324637 |
11 | 475a544909 |
12 | 218408a479 |
13 | 1070c472cc |
14 | 76b48d537 |
15 | 449e37a0c |
hex | 292880e1d |
11048324637 has 16 divisors (see below), whose sum is σ = 17179126400. Its totient is φ = 6313327776.
The previous prime is 11048324629. The next prime is 11048324671. The reversal of 11048324637 is 73642384011.
It is not a de Polignac number, because 11048324637 - 23 = 11048324629 is a prime.
It is a super-3 number, since 3×110483246373 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11048324595 and 11048324604.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11048324237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5367448 + ... + 5369505.
It is an arithmetic number, because the mean of its divisors is an integer number (1073695400).
Almost surely, 211048324637 is an apocalyptic number.
It is an amenable number.
11048324637 is a deficient number, since it is larger than the sum of its proper divisors (6130801763).
11048324637 is an equidigital number, since it uses as much as digits as its factorization.
11048324637 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10736977 (or 10736963 counting only the distinct ones).
The product of its (nonzero) digits is 96768, while the sum is 39.
The spelling of 11048324637 in words is "eleven billion, forty-eight million, three hundred twenty-four thousand, six hundred thirty-seven".
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