Base | Representation |
---|---|
bin | 10100100101001010… |
… | …10101001011110111 |
3 | 1001112001000020000222 |
4 | 22102211111023313 |
5 | 140112043203411 |
6 | 5024222324555 |
7 | 540544413155 |
oct | 122245251367 |
9 | 31461006028 |
10 | 11049194231 |
11 | 475aa89189 |
12 | 218442975b |
13 | 107119006a |
14 | 76b6383d5 |
15 | 44a05a4db |
hex | 2929552f7 |
11049194231 has 4 divisors (see below), whose sum is σ = 11050914000. Its totient is φ = 11047474464.
The previous prime is 11049194209. The next prime is 11049194237. The reversal of 11049194231 is 13249194011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11049194231 - 214 = 11049177847 is a prime.
It is a super-2 number, since 2×110491942312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11049194191 and 11049194200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11049194237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850211 + ... + 863108.
It is an arithmetic number, because the mean of its divisors is an integer number (2762728500).
Almost surely, 211049194231 is an apocalyptic number.
11049194231 is a deficient number, since it is larger than the sum of its proper divisors (1719769).
11049194231 is an equidigital number, since it uses as much as digits as its factorization.
11049194231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1719768.
The product of its (nonzero) digits is 7776, while the sum is 35.
The spelling of 11049194231 in words is "eleven billion, forty-nine million, one hundred ninety-four thousand, two hundred thirty-one".
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