Search a number
-
+
110500421104133 is a prime number
BaseRepresentation
bin11001000111111111100010…
…010110001111001000000101
3112111020201220100010210121222
4121013333202112033020011
5103440414330300313013
61031003105340450125
732163251305646114
oct3107774226171005
9474221810123558
10110500421104133
1132232a68a78435
121048787b549945
1349871b673c678
141d4036b05dc7b
15cb95822c7508
hex647fe258f205

110500421104133 has 2 divisors, whose sum is σ = 110500421104134. Its totient is φ = 110500421104132.

The previous prime is 110500421104037. The next prime is 110500421104141. The reversal of 110500421104133 is 331401124005011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80563962402049 + 29936458702084 = 8975743^2 + 5471422^2 .

It is a cyclic number.

It is not a de Polignac number, because 110500421104133 - 210 = 110500421103109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110500420104133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55250210552066 + 55250210552067.

It is an arithmetic number, because the mean of its divisors is an integer number (55250210552067).

Almost surely, 2110500421104133 is an apocalyptic number.

It is an amenable number.

110500421104133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110500421104133 is an equidigital number, since it uses as much as digits as its factorization.

110500421104133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 110500421104133 its reverse (331401124005011), we get a palindrome (441901545109144).

The spelling of 110500421104133 in words is "one hundred ten trillion, five hundred billion, four hundred twenty-one million, one hundred four thousand, one hundred thirty-three".