Base | Representation |
---|---|
bin | 110011011101010010… |
… | …0111101011011111111 |
3 | 101120020020120211220212 |
4 | 1212322210331123333 |
5 | 3302303113332112 |
6 | 122433125303035 |
7 | 10661255120534 |
oct | 1467244753377 |
9 | 346206524825 |
10 | 110504433407 |
11 | 42956965425 |
12 | 194bb864a7b |
13 | a560b74c04 |
14 | 54c41b0d8b |
15 | 2d1b539522 |
hex | 19ba93d6ff |
110504433407 has 2 divisors, whose sum is σ = 110504433408. Its totient is φ = 110504433406.
The previous prime is 110504433373. The next prime is 110504433421. The reversal of 110504433407 is 704334405011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110504433407 is a prime.
It is a super-2 number, since 2×1105044334072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110504433437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55252216703 + 55252216704.
It is an arithmetic number, because the mean of its divisors is an integer number (55252216704).
Almost surely, 2110504433407 is an apocalyptic number.
110504433407 is a deficient number, since it is larger than the sum of its proper divisors (1).
110504433407 is an equidigital number, since it uses as much as digits as its factorization.
110504433407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 110504433407 its reverse (704334405011), we get a palindrome (814838838418).
The spelling of 110504433407 in words is "one hundred ten billion, five hundred four million, four hundred thirty-three thousand, four hundred seven".
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