Base | Representation |
---|---|
bin | 10000000101001010001… |
… | …011000100010001111011 |
3 | 10220122022220102200002112 |
4 | 100011022023010101323 |
5 | 121101121024311141 |
6 | 2203353050122535 |
7 | 142560123414503 |
oct | 20051213042173 |
9 | 3818286380075 |
10 | 1105051010171 |
11 | 396716539769 |
12 | 15a1bb42044b |
13 | 8028a386ca4 |
14 | 3b6b0246a03 |
15 | 1db291317eb |
hex | 1014a2c447b |
1105051010171 has 2 divisors, whose sum is σ = 1105051010172. Its totient is φ = 1105051010170.
The previous prime is 1105051010159. The next prime is 1105051010179. The reversal of 1105051010171 is 1710101505011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1105051010171 - 230 = 1103977268347 is a prime.
It is a super-2 number, since 2×11050510101712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1105051010179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552525505085 + 552525505086.
It is an arithmetic number, because the mean of its divisors is an integer number (552525505086).
Almost surely, 21105051010171 is an apocalyptic number.
1105051010171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1105051010171 is an equidigital number, since it uses as much as digits as its factorization.
1105051010171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 175, while the sum is 23.
Adding to 1105051010171 its reverse (1710101505011), we get a palindrome (2815152515182).
The spelling of 1105051010171 in words is "one trillion, one hundred five billion, fifty-one million, ten thousand, one hundred seventy-one".
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