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1105106055045 = 35431713342721
BaseRepresentation
bin10000000101001101011…
…101000010111110000101
310220122110202000020110120
4100011031131002332011
5121101224122230140
62203402334012153
7142561362323256
oct20051535027605
93818422006416
101105106055045
113967446157a3
1215a215947059
13802988ba715
143b6b7694b2d
151db2dda61d0
hex1014d742f85

1105106055045 has 16 divisors (see below), whose sum is σ = 1809289914432. Its totient is φ = 575683153920.

The previous prime is 1105106055013. The next prime is 1105106055089. The reversal of 1105106055045 is 5405506015011.

It is not a de Polignac number, because 1105106055045 - 25 = 1105106055013 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1105106054997 and 1105106055015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 856670716 + ... + 856672005.

It is an arithmetic number, because the mean of its divisors is an integer number (113080619652).

Almost surely, 21105106055045 is an apocalyptic number.

1105106055045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1105106055045 is a deficient number, since it is larger than the sum of its proper divisors (704183859387).

1105106055045 is a wasteful number, since it uses less digits than its factorization.

1105106055045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1713342772.

The product of its (nonzero) digits is 15000, while the sum is 33.

The spelling of 1105106055045 in words is "one trillion, one hundred five billion, one hundred six million, fifty-five thousand, forty-five".

Divisors: 1 3 5 15 43 129 215 645 1713342721 5140028163 8566713605 25700140815 73673737003 221021211009 368368685015 1105106055045