Base | Representation |
---|---|
bin | 1010000011010010100100… |
… | …1000110010000011100010 |
3 | 1110010112012212100100001120 |
4 | 2200310221020302003202 |
5 | 2422032230100130032 |
6 | 35301015341513110 |
7 | 2220311652464655 |
oct | 240645110620342 |
9 | 43115185310046 |
10 | 11051641020642 |
11 | 3580a7a271072 |
12 | 12a5a70272796 |
13 | 62221c15cac1 |
14 | 2a2c8bbd789c |
15 | 14272a15262c |
hex | a0d292320e2 |
11051641020642 has 32 divisors (see below), whose sum is σ = 23404011996672. Its totient is φ = 3467101956864.
The previous prime is 11051641020631. The next prime is 11051641020769. The reversal of 11051641020642 is 24602014615011.
It is a super-3 number, since 3×110516410206423 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3306448 + ... + 5747684.
It is an arithmetic number, because the mean of its divisors is an integer number (731375374896).
Almost surely, 211051641020642 is an apocalyptic number.
11051641020642 is an abundant number, since it is smaller than the sum of its proper divisors (12352370976030).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11051641020642 is a wasteful number, since it uses less digits than its factorization.
11051641020642 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2485642.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 11051641020642 its reverse (24602014615011), we get a palindrome (35653655635653).
The spelling of 11051641020642 in words is "eleven trillion, fifty-one billion, six hundred forty-one million, twenty thousand, six hundred forty-two".
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