11052131 has 2 divisors, whose sum is σ = 11052132. Its totient is φ = 11052130.

The previous prime is 11052113. The next prime is 11052169. The reversal of 11052131 is 13125011.

11052131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11052113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11052131 - 2¹⁰ = 11051107 is a prime.

It is a super-2 number, since 2×11052131² = 244299199282322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11052101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526065 + 5526066.

It is an arithmetic number, because the mean of its divisors is an integer number (5526066).

Almost surely, 2^11052131 is an apocalyptic number.

11052131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11052131 is an equidigital number, since it uses as much as digits as its factorization.

11052131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 11052131 is about 3324.4745449469. The cubic root of 11052131 is about 222.7487837112.

Adding to 11052131 its reverse (13125011), we get a palindrome (24177142).

The spelling of 11052131 in words is "eleven million, fifty-two thousand, one hundred thirty-one".