Base | Representation |
---|---|
bin | 10100100101100001… |
… | …00111110111100111 |
3 | 1001112020120121112202 |
4 | 22102300213313213 |
5 | 140113322414333 |
6 | 5024410005115 |
7 | 540611522216 |
oct | 122260476747 |
9 | 31466517482 |
10 | 11052154343 |
11 | 476172015a |
12 | 218541679b |
13 | 10719884c9 |
14 | 76bba907d |
15 | 44a4425e8 |
hex | 292c27de7 |
11052154343 has 2 divisors, whose sum is σ = 11052154344. Its totient is φ = 11052154342.
The previous prime is 11052154339. The next prime is 11052154349. The reversal of 11052154343 is 34345125011.
It is a weak prime.
It is an emirp because it is prime and its reverse (34345125011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11052154343 - 22 = 11052154339 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11052154349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526077171 + 5526077172.
It is an arithmetic number, because the mean of its divisors is an integer number (5526077172).
Almost surely, 211052154343 is an apocalyptic number.
11052154343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11052154343 is an equidigital number, since it uses as much as digits as its factorization.
11052154343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 11052154343 its reverse (34345125011), we get a palindrome (45397279354).
The spelling of 11052154343 in words is "eleven billion, fifty-two million, one hundred fifty-four thousand, three hundred forty-three".
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