Base | Representation |
---|---|
bin | 1010000011010101000010… |
… | …0110011101100001101111 |
3 | 1110010120221000012002001221 |
4 | 2200311100212131201233 |
5 | 2422040104044043203 |
6 | 35301205152444211 |
7 | 2220334242252235 |
oct | 240652046354157 |
9 | 43116830162057 |
10 | 11052303112303 |
11 | 3581289a79362 |
12 | 12a6015b49667 |
13 | 6222c638870b |
14 | 2a2d11b04955 |
15 | 142768337abd |
hex | a0d5099d86f |
11052303112303 has 8 divisors (see below), whose sum is σ = 11349297574160. Its totient is φ = 10759044430080.
The previous prime is 11052303112297. The next prime is 11052303112337. The reversal of 11052303112303 is 30321130325011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11052303112303 - 25 = 11052303112271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11052303112603) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 933938913 + ... + 933950746.
It is an arithmetic number, because the mean of its divisors is an integer number (1418662196770).
Almost surely, 211052303112303 is an apocalyptic number.
11052303112303 is a deficient number, since it is larger than the sum of its proper divisors (296994461857).
11052303112303 is an equidigital number, since it uses as much as digits as its factorization.
11052303112303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1867889817.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 11052303112303 its reverse (30321130325011), we get a palindrome (41373433437314).
The spelling of 11052303112303 in words is "eleven trillion, fifty-two billion, three hundred three million, one hundred twelve thousand, three hundred three".
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