Base | Representation |
---|---|
bin | 10100100101101000… |
… | …10100101110100001 |
3 | 1001112022101220100222 |
4 | 22102310110232201 |
5 | 140114044441023 |
6 | 5024442452425 |
7 | 540623002544 |
oct | 122264245641 |
9 | 31468356328 |
10 | 11053124513 |
11 | 4762223052 |
12 | 2185804115 |
13 | 1071c37c82 |
14 | 76bd7c85b |
15 | 44a584cc8 |
hex | 292d14ba1 |
11053124513 has 4 divisors (see below), whose sum is σ = 11533695168. Its totient is φ = 10572553860.
The previous prime is 11053124497. The next prime is 11053124527. The reversal of 11053124513 is 31542135011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11053124513 - 24 = 11053124497 is a prime.
It is a super-2 number, since 2×110531245132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11053124573) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240285293 + ... + 240285338.
It is an arithmetic number, because the mean of its divisors is an integer number (2883423792).
Almost surely, 211053124513 is an apocalyptic number.
It is an amenable number.
11053124513 is a deficient number, since it is larger than the sum of its proper divisors (480570655).
11053124513 is an equidigital number, since it uses as much as digits as its factorization.
11053124513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 480570654.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 11053124513 its reverse (31542135011), we get a palindrome (42595259524).
The spelling of 11053124513 in words is "eleven billion, fifty-three million, one hundred twenty-four thousand, five hundred thirteen".
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