Base | Representation |
---|---|
bin | 1010000011011010000010… |
… | …0100000010111011011001 |
3 | 1110010201101111112120112022 |
4 | 2200312200210002323121 |
5 | 2422100331013000340 |
6 | 35301550234424225 |
7 | 2220412422221324 |
oct | 240664044027331 |
9 | 43121344476468 |
10 | 11053644656345 |
11 | 3581908271245 |
12 | 12a632b292075 |
13 | 62247b2aac65 |
14 | 2a2ddbd5b7bb |
15 | 1427e5ed23b5 |
hex | a0da0902ed9 |
11053644656345 has 4 divisors (see below), whose sum is σ = 13264373587620. Its totient is φ = 8842915725072.
The previous prime is 11053644656297. The next prime is 11053644656347. The reversal of 11053644656345 is 54365644635011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3743369778841 + 7310274877504 = 1934779^2 + 2703752^2 .
It is a cyclic number.
It is not a de Polignac number, because 11053644656345 - 26 = 11053644656281 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11053644656347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1105364465630 + ... + 1105364465639.
It is an arithmetic number, because the mean of its divisors is an integer number (3316093396905).
Almost surely, 211053644656345 is an apocalyptic number.
It is an amenable number.
11053644656345 is a deficient number, since it is larger than the sum of its proper divisors (2210728931275).
11053644656345 is an equidigital number, since it uses as much as digits as its factorization.
11053644656345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2210728931274.
The product of its (nonzero) digits is 15552000, while the sum is 53.
The spelling of 11053644656345 in words is "eleven trillion, fifty-three billion, six hundred forty-four million, six hundred fifty-six thousand, three hundred forty-five".
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