Base | Representation |
---|---|
bin | 1010000011011010001000… |
… | …0101011011100000010011 |
3 | 1110010201110021120120020021 |
4 | 2200312202011123200103 |
5 | 2422100404031404404 |
6 | 35301552545524311 |
7 | 2220413152214662 |
oct | 240664205334023 |
9 | 43121407516207 |
10 | 11053670184979 |
11 | 3581920718294 |
12 | 12a6337943697 |
13 | 622483678966 |
14 | 2a30014c4dd9 |
15 | 1427e8376454 |
hex | a0da215b813 |
11053670184979 has 2 divisors, whose sum is σ = 11053670184980. Its totient is φ = 11053670184978.
The previous prime is 11053670184971. The next prime is 11053670185003. The reversal of 11053670184979 is 97948107635011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11053670184979 - 23 = 11053670184971 is a prime.
It is not a weakly prime, because it can be changed into another prime (11053670184971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526835092489 + 5526835092490.
It is an arithmetic number, because the mean of its divisors is an integer number (5526835092490).
Almost surely, 211053670184979 is an apocalyptic number.
11053670184979 is a deficient number, since it is larger than the sum of its proper divisors (1).
11053670184979 is an equidigital number, since it uses as much as digits as its factorization.
11053670184979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11430720, while the sum is 61.
The spelling of 11053670184979 in words is "eleven trillion, fifty-three billion, six hundred seventy million, one hundred eighty-four thousand, nine hundred seventy-nine".
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