Base | Representation |
---|---|
bin | 1010000011011010001000… |
… | …0101011011100000101011 |
3 | 1110010201110021120120021011 |
4 | 2200312202011123200223 |
5 | 2422100404031410003 |
6 | 35301552545524351 |
7 | 2220413152215025 |
oct | 240664205334053 |
9 | 43121407516234 |
10 | 11053670185003 |
11 | 3581920718306 |
12 | 12a63379436b7 |
13 | 622483678984 |
14 | 2a30014c5015 |
15 | 1427e837646d |
hex | a0da215b82b |
11053670185003 has 2 divisors, whose sum is σ = 11053670185004. Its totient is φ = 11053670185002.
The previous prime is 11053670184979. The next prime is 11053670185007. The reversal of 11053670185003 is 30058107635011.
It is a strong prime.
It is an emirp because it is prime and its reverse (30058107635011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11053670185003 - 25 = 11053670184971 is a prime.
It is a super-2 number, since 2×110536701850032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11053670185007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526835092501 + 5526835092502.
It is an arithmetic number, because the mean of its divisors is an integer number (5526835092502).
Almost surely, 211053670185003 is an apocalyptic number.
11053670185003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11053670185003 is an equidigital number, since it uses as much as digits as its factorization.
11053670185003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75600, while the sum is 40.
The spelling of 11053670185003 in words is "eleven trillion, fifty-three billion, six hundred seventy million, one hundred eighty-five thousand, three".
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