Base | Representation |
---|---|
bin | 10100100101110001… |
… | …10110111111101111 |
3 | 1001112101122022021212 |
4 | 22102320312333233 |
5 | 140114401012310 |
6 | 5024524145035 |
7 | 540636054053 |
oct | 122270667757 |
9 | 31471568255 |
10 | 11054313455 |
11 | 4762965349 |
12 | 218609817b |
13 | 10722631a3 |
14 | 76c1abc63 |
15 | 44a71c205 |
hex | 292e36fef |
11054313455 has 16 divisors (see below), whose sum is σ = 13564605600. Its totient is φ = 8645489280.
The previous prime is 11054313401. The next prime is 11054313469. The reversal of 11054313455 is 55431345011.
It is not a de Polignac number, because 11054313455 - 210 = 11054312431 is a prime.
It is a super-2 number, since 2×110543134552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50120 + ... + 156909.
It is an arithmetic number, because the mean of its divisors is an integer number (847787850).
Almost surely, 211054313455 is an apocalyptic number.
11054313455 is a deficient number, since it is larger than the sum of its proper divisors (2510292145).
11054313455 is a wasteful number, since it uses less digits than its factorization.
11054313455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 207274.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 11054313455 its reverse (55431345011), we get a palindrome (66485658466).
The spelling of 11054313455 in words is "eleven billion, fifty-four million, three hundred thirteen thousand, four hundred fifty-five".
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