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11055544530523 is a prime number
BaseRepresentation
bin1010000011100001000111…
…0011011111011001011011
31110010220021220111011221121
42200320101303133121123
52422113223344434043
635302502543350111
72220510461665153
oct240702163373133
943126256434847
1011055544530523
1135826a2740899
1212a677b5b2337
136226c1a9946c
142a313c3d1763
151428a7bb7ded
hexa0e11cdf65b

11055544530523 has 2 divisors, whose sum is σ = 11055544530524. Its totient is φ = 11055544530522.

The previous prime is 11055544530509. The next prime is 11055544530529. The reversal of 11055544530523 is 32503544555011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11055544530523 - 25 = 11055544530491 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11055544530523.

It is not a weakly prime, because it can be changed into another prime (11055544530529) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5527772265261 + 5527772265262.

It is an arithmetic number, because the mean of its divisors is an integer number (5527772265262).

Almost surely, 211055544530523 is an apocalyptic number.

11055544530523 is a deficient number, since it is larger than the sum of its proper divisors (1).

11055544530523 is an equidigital number, since it uses as much as digits as its factorization.

11055544530523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900000, while the sum is 43.

The spelling of 11055544530523 in words is "eleven trillion, fifty-five billion, five hundred forty-four million, five hundred thirty thousand, five hundred twenty-three".