Search a number
-
+
11056302616213 is a prime number
BaseRepresentation
bin1010000011100011111011…
…1111010110111010010101
31110010222020201221221000101
42200320332333112322111
52422121301432204323
635303110104014101
72220535325421421
oct240707677267225
943128221857011
1011056302616213
113582a51653898
1212a6951461331
136227b2b6538a
142a31b0d69b81
151428ee510dad
hexa0e3efd6e95

11056302616213 has 2 divisors, whose sum is σ = 11056302616214. Its totient is φ = 11056302616212.

The previous prime is 11056302616141. The next prime is 11056302616243. The reversal of 11056302616213 is 31261620365011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7240366968849 + 3815935647364 = 2690793^2 + 1953442^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11056302616213 is a prime.

It is a super-3 number, since 3×110563026162133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11056302616243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5528151308106 + 5528151308107.

It is an arithmetic number, because the mean of its divisors is an integer number (5528151308107).

Almost surely, 211056302616213 is an apocalyptic number.

It is an amenable number.

11056302616213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11056302616213 is an equidigital number, since it uses as much as digits as its factorization.

11056302616213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 11056302616213 in words is "eleven trillion, fifty-six billion, three hundred two million, six hundred sixteen thousand, two hundred thirteen".