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11056313243035 = 57330291269159
BaseRepresentation
bin1010000011100011111110…
…0111111001010110011011
31110010222021110221211021101
42200320333213321112123
52422121312142234120
635303111123452231
72220535514641414
oct240707747712633
943128243854241
1011056313243035
113582a57651995
1212a6954b27077
136227b5116338
142a31b253480b
1514290040e90a
hexa0e3f9f959b

11056313243035 has 8 divisors (see below), whose sum is σ = 13449323507040. Its totient is φ = 8723885517504.

The previous prime is 11056313243009. The next prime is 11056313243039. The reversal of 11056313243035 is 53034231365011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11056313243035 - 219 = 11056312718747 is a prime.

It is a super-2 number, since 2×110563132430352 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11056313242985 and 11056313243003.

It is not an unprimeable number, because it can be changed into a prime (11056313243039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15145634215 + ... + 15145634944.

It is an arithmetic number, because the mean of its divisors is an integer number (1681165438380).

Almost surely, 211056313243035 is an apocalyptic number.

11056313243035 is a deficient number, since it is larger than the sum of its proper divisors (2393010264005).

11056313243035 is an equidigital number, since it uses as much as digits as its factorization.

11056313243035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30291269237.

The product of its (nonzero) digits is 97200, while the sum is 37.

The spelling of 11056313243035 in words is "eleven trillion, fifty-six billion, three hundred thirteen million, two hundred forty-three thousand, thirty-five".

Divisors: 1 5 73 365 30291269159 151456345795 2211262648607 11056313243035