Base | Representation |
---|---|
bin | 1010000011100100100010… |
… | …1000101000101111110001 |
3 | 1110010222200000110000200212 |
4 | 2200321020220220233301 |
5 | 2422122114343311423 |
6 | 35303134124153505 |
7 | 2220542332013042 |
oct | 240711050505761 |
9 | 43128600400625 |
10 | 11056464432113 |
11 | 3583024a26541 |
12 | 12a6997698895 |
13 | 62280a540529 |
14 | 2a31c864c8c9 |
15 | 14290d826578 |
hex | a0e48a28bf1 |
11056464432113 has 2 divisors, whose sum is σ = 11056464432114. Its totient is φ = 11056464432112.
The previous prime is 11056464432109. The next prime is 11056464432133. The reversal of 11056464432113 is 31123446465011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9185948673889 + 1870515758224 = 3030833^2 + 1367668^2 .
It is a cyclic number.
It is not a de Polignac number, because 11056464432113 - 22 = 11056464432109 is a prime.
It is not a weakly prime, because it can be changed into another prime (11056464432133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5528232216056 + 5528232216057.
It is an arithmetic number, because the mean of its divisors is an integer number (5528232216057).
Almost surely, 211056464432113 is an apocalyptic number.
It is an amenable number.
11056464432113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11056464432113 is an equidigital number, since it uses as much as digits as its factorization.
11056464432113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 41.
The spelling of 11056464432113 in words is "eleven trillion, fifty-six billion, four hundred sixty-four million, four hundred thirty-two thousand, one hundred thirteen".
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