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11056464432133 is a prime number
BaseRepresentation
bin1010000011100100100010…
…1000101000110000000101
31110010222200000110000201121
42200321020220220300011
52422122114343312013
635303134124153541
72220542332013101
oct240711050506005
943128600400647
1011056464432133
113583024a2655a
1212a69976988b1
1362280a540543
142a31c864c901
1514290d82658d
hexa0e48a28c05

11056464432133 has 2 divisors, whose sum is σ = 11056464432134. Its totient is φ = 11056464432132.

The previous prime is 11056464432113. The next prime is 11056464432161. The reversal of 11056464432133 is 33123446465011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10977605683009 + 78858749124 = 3313247^2 + 280818^2 .

It is a cyclic number.

It is not a de Polignac number, because 11056464432133 - 217 = 11056464301061 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11056464432133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11056464432113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5528232216066 + 5528232216067.

It is an arithmetic number, because the mean of its divisors is an integer number (5528232216067).

Almost surely, 211056464432133 is an apocalyptic number.

It is an amenable number.

11056464432133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11056464432133 is an equidigital number, since it uses as much as digits as its factorization.

11056464432133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 43.

The spelling of 11056464432133 in words is "eleven trillion, fifty-six billion, four hundred sixty-four million, four hundred thirty-two thousand, one hundred thirty-three".