Base | Representation |
---|---|
bin | 1010000011101101100110… |
… | …1000010011101001011101 |
3 | 1110011012221112211102010211 |
4 | 2200323121220103221131 |
5 | 2422142110120321023 |
6 | 35304215343332421 |
7 | 2220656530605142 |
oct | 240733150235135 |
9 | 43135845742124 |
10 | 11058897042013 |
11 | 3584063091347 |
12 | 12a73562b1111 |
13 | 622b07506082 |
14 | 2a337975a3c9 |
15 | 142a0218ea0d |
hex | a0ed9a13a5d |
11058897042013 has 2 divisors, whose sum is σ = 11058897042014. Its totient is φ = 11058897042012.
The previous prime is 11058897042007. The next prime is 11058897042133. The reversal of 11058897042013 is 31024079885011.
11058897042013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10427487222244 + 631409819769 = 3229162^2 + 794613^2 .
It is a cyclic number.
It is not a de Polignac number, because 11058897042013 - 25 = 11058897041981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11058894042013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5529448521006 + 5529448521007.
It is an arithmetic number, because the mean of its divisors is an integer number (5529448521007).
Almost surely, 211058897042013 is an apocalyptic number.
It is an amenable number.
11058897042013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11058897042013 is an equidigital number, since it uses as much as digits as its factorization.
11058897042013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 49.
The spelling of 11058897042013 in words is "eleven trillion, fifty-eight billion, eight hundred ninety-seven million, forty-two thousand, thirteen".
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