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11061105479981 is a prime number
BaseRepresentation
bin1010000011110101110101…
…0000110101000100101101
31110011102122110101200111122
42200331131100311010231
52422211121000324411
635305222434030325
72221065335166614
oct240753520650455
943142573350448
1011061105479981
113584a96754497
1212a7871a183a5
13623099c002bb
142a3508b9287b
15142ad0ec69db
hexa0f5d43512d

11061105479981 has 2 divisors, whose sum is σ = 11061105479982. Its totient is φ = 11061105479980.

The previous prime is 11061105479933. The next prime is 11061105479987. The reversal of 11061105479981 is 18997450116011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6036559077481 + 5024546402500 = 2456941^2 + 2241550^2 .

It is a cyclic number.

It is not a de Polignac number, because 11061105479981 - 234 = 11043925610797 is a prime.

It is a super-3 number, since 3×110611054799813 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11061105479987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5530552739990 + 5530552739991.

It is an arithmetic number, because the mean of its divisors is an integer number (5530552739991).

Almost surely, 211061105479981 is an apocalyptic number.

It is an amenable number.

11061105479981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11061105479981 is an equidigital number, since it uses as much as digits as its factorization.

11061105479981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 53.

The spelling of 11061105479981 in words is "eleven trillion, sixty-one billion, one hundred five million, four hundred seventy-nine thousand, nine hundred eighty-one".