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1106231153 = 7431488871
BaseRepresentation
bin100000111101111…
…1011111101110001
32212002120100212012
41001323323331301
54231143344103
6301434212305
736261544466
oct10173737561
92762510765
101106231153
11518490925
1226a584095
13148252c61
14a6cc166d
15671b72d8
hex41efbf71

1106231153 has 4 divisors (see below), whose sum is σ = 1107720768. Its totient is φ = 1104741540.

The previous prime is 1106231141. The next prime is 1106231173. The reversal of 1106231153 is 3511326011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1106231153 - 210 = 1106230129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1106231173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 743693 + ... + 745178.

It is an arithmetic number, because the mean of its divisors is an integer number (276930192).

Almost surely, 21106231153 is an apocalyptic number.

It is an amenable number.

1106231153 is a deficient number, since it is larger than the sum of its proper divisors (1489615).

1106231153 is an equidigital number, since it uses as much as digits as its factorization.

1106231153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1489614.

The product of its (nonzero) digits is 540, while the sum is 23.

The square root of 1106231153 is about 33260.0534124646. The cubic root of 1106231153 is about 1034.2256269037.

Adding to 1106231153 its reverse (3511326011), we get a palindrome (4617557164).

The spelling of 1106231153 in words is "one billion, one hundred six million, two hundred thirty-one thousand, one hundred fifty-three".

Divisors: 1 743 1488871 1106231153