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11063352424549 is a prime number
BaseRepresentation
bin1010000011111110001100…
…1100001111100001100101
31110011122110001102021222211
42200333203030033201211
52422230221210041144
635310233421523421
72221205120666455
oct240774314174145
943148401367884
1011063352424549
113585a3a028177
1212a819a413571
1362336758a3b9
142a367d36dd65
15142bb33b8034
hexa0fe330f865

11063352424549 has 2 divisors, whose sum is σ = 11063352424550. Its totient is φ = 11063352424548.

The previous prime is 11063352424471. The next prime is 11063352424571. The reversal of 11063352424549 is 94542425336011.

11063352424549 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10301211202500 + 762141222049 = 3209550^2 + 873007^2 .

It is a cyclic number.

It is not a de Polignac number, because 11063352424549 - 233 = 11054762489957 is a prime.

It is a super-5 number, since 5×110633524245495 (a number of 66 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11063352404549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5531676212274 + 5531676212275.

It is an arithmetic number, because the mean of its divisors is an integer number (5531676212275).

Almost surely, 211063352424549 is an apocalyptic number.

It is an amenable number.

11063352424549 is a deficient number, since it is larger than the sum of its proper divisors (1).

11063352424549 is an equidigital number, since it uses as much as digits as its factorization.

11063352424549 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3110400, while the sum is 49.

The spelling of 11063352424549 in words is "eleven trillion, sixty-three billion, three hundred fifty-two million, four hundred twenty-four thousand, five hundred forty-nine".